Quoestion:Find the point of intersection of two singly linked lists begins.
Algorithm:
1.Calculate the size of both linked lists as L1,L2
2.Find the absolute difference of L1,L2 as d = L1-L2
3.Move d nodes in longer linked list
4.Then move by one step in both Linked Lists and Check if p==q if they are eaqual return p




Python Code:
# Definition for singly-linked list.
class ListNode:
    def __init__(self, x):
        self.val = x
        self.next = None

 class Solution:
    def getIntersectionNode(self, headA: ListNode, headB: ListNode) -> ListNode:
        l1size,l2size = 0,0
        node = headA
        while node:
            l1size+=1
            node = node.next
        node = headB
        while node:
            node = node.next
            l2size+=1
        d = abs(l1size-l2size)
        # print(d,l1size,l2size)
        if l1size>l2size:
            for i in range(d):
                headA = headA.next
            # print(headA.val)
        else:
            for i in range(d):
                headB = headB.next
            
        while True:
            if headA == headB:
                return headA
            
            if headA:
                headA = headA.next
            else:
                break
            if headB:
                headB = headB.next
            else:
                break
            # print(headA.val,headB.val)
        return