Remove Nth Node From End of List LeetCode Solution

Quoestion: ClickHere



Algorithm:
step1:intialize slow and fast pointers with head
step2:Move forward fast pointer by n positions
step3:if fast.next is None then return head.next
step4:Move forward fast and slow pointers by one step until fast.next == None.
step5:slow.next = slow.next.next

Python Code 
class Solution:
    def removeNthFromEnd(self, head: ListNode, n: int) -> ListNode:
        slow = fast = head
        for i in range(n):
            print(fast.val)
            fast = fast.next
        if fast is None:
            return head.next
        while fast.next:
            print(fast.val,slow.val)
            fast= fast.next
            slow = slow.next
        slow.next = slow.next.next
        return head